The de - Broglie wavelength lambda...

The de - Broglie wavelength `lambda`

mass of the particle

size of the particle

material of the particle

shape of the particle

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de-Broglie wavelength lambda is

The de-Broglie wavelength lamda

Two particles having de-Broglie wavelengths lambda_(1) and lambda_(2) , while moving along mutually perpendicular directions, undergo perfectly inelastic collision. The de-Broglie wavelength lambda , of the final particle is

A nucleus A, With a finite de-broglie wavelength lambda_(A) , undergoes spontaneous fission into two nuclei B and C of equal mass. B flies in the same direction as that of A, While C flies in the opposite direction with a velocity equal to half of that of B . The de-Broglie wavelength lambda_(B) and lambda_(B) and C are respectively:

A photon of frequency v causes photo electric emission from a surface with threshold frequency v_(0) . The de-Broglies wavelength (lambda) of the photo electron emitted is given by:

A nucleus at rest undergoes a decay emitting an a particle of de - Broglie wavelength lambda = 5.76 xx 10^(-15)m if the mass of particle is 4.002amu , determine the total kinetic energy in the final state Hence , obratain the mass of the parent nucleus in amu (1 amu = 931.470 MeV//e^(2))

A charged particle is associated from rest through a certain potential difference. The de-Broglie wavelength is lambda_(1) when it is accelerated through V_(1) and is lambda_(2) when accelerated through V_(2) . The ratio lambda_(1)//lambda_(2) is

A proton and an electron are accelerated by same potential difference have de-Broglie wavelength lambda_(p) and lambda_(e ) .

Eleactrons kept in an encloser at temperature T have a de-Broglie wavelength lambda . If the temperature of the encloser is increased, then the de Broglie wavelength of the electrons will

The log - log graph between the energy E of an electron and its de - Broglie wavelength lambda will be

NARAYNA-DUAL NATURE-C.U.Q

When an X-ray photon collides with an electrons and bounces off, its n...
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The de - Broglie wavelength lambda
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Choose the correct statement
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The momentum of a proton is p. the corresponding wavelength is
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A wave is associated with matter when it is
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An electron of mass 9.1xx10^(-31) kg and charge 1.6xx10^(-19) C is acc...
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The de Broglie wavelength of a molecules of thermal energy KT ( K is B...
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The wavelength of a proton and a photon are same. Then
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Matter waves are:
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The incorrect statement is
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