Home
Class 12
PHYSICS
Two photons of energies twice and thrice...

Two photons of energies twice and thrice the work function of a metal are incident on the metal surface. Then the ratio of maximum velocity of the photoelectrons emitted in the two cases respectively, is

A

`sqrt2:1`

B

`sqrt3:1`

C

`sqrt3:2`

D

`sqrt1:2`

Text Solution

Verified by Experts

The correct Answer is:
D
`V_(1)/V_(2)=sqrt((E_(1)-omega_(0))/(E_(2)-omega_(0)))`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • DUAL NATURE

    NARAYNA|Exercise LEVEL-II (H.W)|17 Videos

  • DUAL NATURE

    NARAYNA|Exercise LEVEL-I(H.W)|7 Videos

  • DUAL NATURE OF RADIATION AND MATTER

    NARAYNA|Exercise ASSERTION AND REASON|15 Videos

  • ELECTRIC CHARGES AND FIELDS

    NARAYNA|Exercise EXERCISE -4|43 Videos

Similar Questions

Explore conceptually related problems

Radiations of two photon’s energy, twice and ten times the work function of metal are incident on the metal surface successsively. The ratio of maximum velocities of photoelectrons emitted in two cases is

Two stream of photons, possessing energies equal to twice and ten times the work function of metal are incident on the metal surface successively. The value of ratio of maximum velocities of the photoelectrons emitted in the two respective cases is x : y. The value of x is ...............

Knowledge Check

  • Radiation two photons having energies twice and five times the work function of a metal are incident successively on the metal surface. The ratio of the maximum velocity of photoelectrons emitted in the two cases will be

    A
    `1:2`
    B
    `2:1`
    C
    `1:4`
    D
    `4:1`

  • The work function of a metal is 2.5 eV. Light of wavelength 3600 Å is incident on this metal surface. The velocity of emitted photoelectrons will be

    A
    `3.8xx10^6m//s`
    B
    `5.2 xx10^4 m//s`
    C
    `4xx10^4m//s`
    D
    `6xx10^5 m//s`

  • Photons of energy 1.5 eV and 2.5 eV are incident on a metal surface of work function 0.5 eV. What is the ratio of the maximum kinetic energy of the photoelectrons ?

    A
    `1:2`
    B
    2
    C
    3
    D
    `1:4`

    • Similar Questions

    Explore conceptually related problems

    Two differenct photons of energies, 1 eV and 2.5 eV, fall on two identical metal plates having work function 0.5 eV, Then the ratio of maximum KE of the electrons emitted from the two surface is -

    The work function of metal is 1 eV . Light of wavelength 3000 Å is incident on this metal surface . The velocity of emitted photo - electrons will be

    Light of wavelength 3000Å is incident on a metal surface whose work function is 1 eV. The maximum velocity of emitted photoelectron will be

    Light of wavelength 3000 Å is incident on a metal surface whose work function is 1 e V. The maximum velocity of emitted photoelectrons will be

    Monochromatic photons of energy 3.3 eV are incident on a photo sensitive surface of work function 2.4 eV. , maximum velocity of photoelectron is

    Home
    Profile