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Two photons of energies twice and thrice...

Two photons of energies twice and thrice the work function of a metal are incident on the metal surface. Then the ratio of maximum velocity of the photoelectrons emitted in the two cases respectively, is

A

`sqrt2:1`

B

`sqrt3:1`

C

`sqrt3:2`

D

`sqrt1:2`

Text Solution

Verified by Experts

The correct Answer is:
D
`V_(1)/V_(2)=sqrt((E_(1)-omega_(0))/(E_(2)-omega_(0)))`
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