Home
Class 11
MATHS
[" The equation of the parabola whose fo...

[" The equation of the parabola whose focus is "],[(1,1)" and tangent at the vertex is "x+y=1],[" is "]

Promotional Banner

Similar Questions

Explore conceptually related problems

Find the equation of the parabola whose focus is (1,1) and tangent at the vertex is x+y=1

Find the equation of the parabola whose focus is (1, 1) and tangent at the vertex is x + y= 1.

Prove that the equation of the parabola whose focus is (0, 0) and tangent at the vertex is x-y+1 = 0 is x^2 + y^2 + 2xy - 4x + 4y - 4=0 .

Prove that the equation of the parabola whose focus is (0, 0) and tangent at the vertex is x-y+1 = 0 is x^2 + y^2 + 2xy - 4x + 4y - 4=0 .

Prove that the equation of the parabola whose focus is (0, 0) and tangent at the vertex is x-y+1 = 0 is x^2 + y^2 + 2xy - 4x + 4y - 4=0 .

Prove that the equation of the parabola whose focus is (0, 0) and tangent at the vertex is x-y+1 = 0 is x^2 + y^2 + 2xy - 4x + 4y - 4=0 .

Prove that the equation of the parabola whose focus is (0, 0) and tangent at the vertex is x-y+1 = 0 is x^2 + y^2 + 2xy - 4x + 4y - 4=0 .

the equation of the parabola whose focus is the point (0,0) and the tangent at the vertix is x-y+1=0 is

the equation of the parabola whose focus is the point (0,0) and the tangent at the vertix is x-y+1=0 is