(1)/(1-cos theta+2i sin theta)

Write the following in the form x + iy : 1/(1- cos theta +2 i sin theta) .

If x + iy = (1)/(1-cos theta + 2 i sin theta), theta ne 2n pi, n in I , then maximum value of x is

(1+cos theta+i sin theta)^(10)+(1+cos theta-i sin theta)^(10)=

Prove the following identity : (sin theta)/(1+cos theta)+ (sin theta)/(1-cos theta)= 2/(sin theta) .

Prove each of the following identities : (i) (1+ cos theta + sin theta)/(1+ cos theta - sin theta) =(1+ sin theta)/(cos theta) (ii) (sin theta + 1- cos theta)/(cos theta - 1 + sin theta) = (1+ sin theta)/(cos theta)

The value of (1+cos theta+i sin theta)^(n)+(1+cos theta-i sin theta)^n=

The value of (1+cos theta+i sin theta)^(n)+(1+cos theta-i sin theta)^(n)=

If theta=(pi)/(6) then the 10^(th) term of the series : 1+(cos theta+i sin theta)^(1)+(cos theta+i sin theta)^(2)+

if theta=(pi)/(6) then the 10 th term of the series 1+(cos theta+i sin theta)^(1)+(cos theta+i sin theta)^(2)+

Prove that ((1+cos theta+i sin theta)/(1+cos theta-i sin theta))^(n)=cos n theta+i sin n theta