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If M be a square matrix of order 3 such...

If M be a square matrix of order 3 such that `|M|=2`, then `|adj((M)/(2))|` equals to :

A

`(1)/(2)`

B

`(1)/(4)`

C

`(1)/(8)`

D

`(1)/(16)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the value of \(|\text{adj}\left(\frac{M}{2}\right)|\) given that \(|M| = 2\) and \(M\) is a square matrix of order 3. ### Step-by-Step Solution: 1. **Understanding the determinant of \(\frac{M}{2}\)**: The determinant of a scalar multiple of a matrix can be expressed as: \[ |kM| = k^n |M| \] where \(n\) is the order of the matrix and \(k\) is the scalar. In this case, \(k = \frac{1}{2}\) and \(n = 3\). Therefore, \[ \left|\frac{M}{2}\right| = \left(\frac{1}{2}\right)^3 |M| = \frac{1}{8} \cdot 2 = \frac{1}{4} \] 2. **Finding the determinant of the adjoint of \(\frac{M}{2}\)**: The determinant of the adjoint of a matrix \(X\) is given by: \[ |\text{adj}(X)| = |X|^{n-1} \] where \(n\) is the order of the matrix. Here, \(X = \frac{M}{2}\) and \(n = 3\). Thus, \[ |\text{adj}\left(\frac{M}{2}\right)| = \left|\frac{M}{2}\right|^{3-1} = \left|\frac{M}{2}\right|^{2} \] 3. **Substituting the value of \(|\frac{M}{2}|\)**: We already calculated that \(\left|\frac{M}{2}\right| = \frac{1}{4}\). Now we substitute this value: \[ |\text{adj}\left(\frac{M}{2}\right)| = \left(\frac{1}{4}\right)^{2} = \frac{1}{16} \] ### Final Answer: Thus, the value of \(|\text{adj}\left(\frac{M}{2}\right)|\) is \(\frac{1}{16}\). ---
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