The value of gravitational acceleration 'g' at a height 'h' above the earth's surface is `(g)/(4)`, then (R = __________ ) (where R = radius of the earth)

The value of gravitational accelerationg at a height h above the earth's surface is then (R = radius of earth)

At what height h above the earth's surface, the value of g becomes g/2 (where R is the radius of the earth)

The value of gravitational accelerationg at a height h above the earth's surface is 0ne forth the value of gravitational acceleration at surface ,then (R = radius of earth)

Show that acceleration due to gravity at height h above the Earth’s surface is g_h = g ((R )/(R+h))^2

Assume that the earth is a uniform sphere of radius R. If the acceleration due to gravity at a height h above the earth's surface is g_1 and at the same depth below the surface of the earth is g_2(h lt R) , then show that, g_2=g_1(1-h/R)(1+h/R)^2 .

Gravitational potential energy of a body of mass m at a height of h above the surface of earth (M = mass of earth,.R = radius of earth) is:

Gravitational potential energy of body of mass m at a height of h above the surface of earth (M = mass of earth , R = radius of earth) is

Gravitational potential energy of body of mass m at a height of h above the surface of earth (M = mass of earth , R = radius of earth) is