The weight of silver (at `wt. = 108`) displaced by a quantity of electricity which displaced `5600 mL` of `O_(2)` at `STP` will be:

Options

A. 5.4 g
B. 10.8 g
C. 54.0 g
D. 108.0 g

Answer

C

Explanation

Since 22400 mL volue is occuiped by 1 mole of `O_(2)` at STP
`therefore` Weight `O_(2) =1/4 xx32 = 8g`
according to problem
Equivalents of Ag = Equivalents of `O_(2)`
`("weight of Ag") /("Equivalent weight of Ag")=("Weight of " O_(2))/("Equivalent weight of " O_(2))`
`rarr W_(Ag)=108 g`