When `0.1 mol MnO_(4)^(2-)` is oxidized the quantity of electricity required to completely oxidize `MnO_(4)^(2-)` to `MnO_(4)^(-)` is

Options

A. 996500 C
B. 2x96500 C
C. 9650 C
D. 96.50 C

Answer

D

Explanation

`MnO_(4)^(2+)overset(1e^(-)[=1f]rarr Mn_(4)^(-)`
For 1 mole of `MnO_(4)^(2-)` 1 F of electricity is required thus for 0.1 mole of `MnO_(4)^(2-) 1 F` electricity is required thus for 0.1 mole of `MnO_(4)^(2-)` 0.1 electricity is required since 1 F =96500 c
`therefore 0.1 F =0.1xx96500C= 9650 C`
Hence 9650 C of electricity is required to completely oxidise `MnO_(4)^(2-)` to `MnO_(4)^(-)`