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When a certain conductivity cell was fi...

When a certain conductivity cell was filled with 0.01 M solution of KCI it had a resistance of 160 `omega` at `25^(@)C` and when filled with 0.005 M NaOH it had a resistance of 190 `omega` if specific resistance of KCI solution is 700 `omega` cm specific conductance `(omega^(-1) cm^(-1))` of NaOH solution is

A

`0.00120`

B

`0.00170`

C

`0.00180`

D

`0.00190`

Text Solution

Verified by Experts

The correct Answer is:
A
Resitance = specific resistance `xx` cell constant
`R_(KcI) =S_(KCI) xx "cell constant"`
`therefore S_(NaOH)=831.25 omega cm`
`therefore` specific conductance `= 1(s)_(NaOH`
`(k)_(NaOH)=1.20 xx10^(-3) omega^(-1) cm^(-1)`
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