The ionic conductance of `H^(+)` and `SO_(4)^(2-)` are 350 and `80 S cm^(2) "equiv"^(-1)` hence equivalent conductance `S cms^(2) "equivalent"^(-1)` and molar conductance `S cm^(2)"mol"^(-1)` of `H_(2)SO_(4)` will be

Options

A. `430, 430`
B. `860, 430`
C. `215 , 430`
D. `430, 860`

Answer

D

Explanation

`wedge_(eq)=lambda^(infty)(H^(+))+lambda^(infty)(SO_(4)^(2-))`
`=80+350=430 S cm^(2) "equivalent"^(-1)`
Since molar mass of `H_(2)SO_(4)=98=2xx"equivalent"^(-1) mass`

`wedge_(m)=2xx430 =860 S cms^(2) "mol"^(-1)`