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E(Fe^(3+)//Fe)^(@)=-0.036V,E(Fe^(2+)//Fe...

`E_(Fe^(3+)//Fe)^(@)=-0.036V,E_(Fe^(2+)//Fe)^(@)=-0.0439V`. The value of standard electrode potential for the change, `Fe^(3+)(aq)+e^(-)toFe^(2+)(aq)` will be

A

`-0.072 V`

B

`0.385 V`

C

`0.770 V`

D

`-0.270 V`

Text Solution

Verified by Experts

The correct Answer is:
A

Given `Fe^(3+) +3e^(-) rarr Fe, E_(1)^(@) =- 0.036 V`
`Fe^(2+) +2e^(-) rarr Fe, E_(2)^(@)=- 0.439V`
We need to calculate
`Fe^(3+) +e^(-) rarr Fe^(2+), E_(3)^(@) =?`
`triangle G_(3) = triangle G_(2) (triangle "G is an extensive property")`
`triangle G_(3) =3xx0.036V-2xx0.0439 V`
`triangle G_(3) =0.108 V - 0.878 V`
`-1 xxV xxE_(3) =- 0.770 V`
`E_(3)^(@) =0.770 v`
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