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Standard electrode potential data are u...

Standard electrode potential data are useful for understanding the suitability of an oxidant in a redox titration some half cell reactions and their standard potentials are given below
`MnO_(4)^(-)(aq)+8H^(+)(aq)+5e^(-)rarrMn^(2+)(Aq)+4H_(2)O(l)^(@)=1.51 V`
`Cr_(2)O_(7)^(2-)(Aq)+14 H^(+)(aq)+6e^(-)rarr2cr^(3+)(aq)+7H_(2)O(l),E^(2)=1.38 V`
`CI_(2)(g)+2e^(-)rarr2CI^(-)(aq),E^(@)=1.40 V`
Identify the incorrect statement regarding the qunatitavite estimation of gaseous `Fe(NO_(3))_(2)`

A

`MnO_(4)^(-)` can be used in aqueous HCI

B

`Cr_(2)O_(7)^(2-)` can be used in aqueous HCI

C

`MnO_(4)^(-)` can be used in aqueous `H_(2)SO_(4)`

D

`Cr_(2)O_(7)^(2-)` can be used in aqueous `H_(2)SO_(4)`

Text Solution

Verified by Experts

The correct Answer is:
B

The reaction between `MnO_(4)^(-)` and HCI may be represented as follows
`2MnO_(4)^(-) (aq)+16H^(+) +10CI^(-) rarr 2Mn^(2+) (aq)+8H_(2)O(I)+5CI_(2)(g)`
Thus on the basis of this reaction following electrochemcial cell will be represented as
since `E_(cell)^(2)=e_(cathode)^(@) -E_(anode)^(2)`
`E_(cell)^(@)` is positive hence `triangle G^(@)` is negative thus above celll reaction is feasible but `MnO_(4)^(-1)` ion can oxidse `Fe^(2+)` to `Fe^(3+)` and `CI^(-)` to `CI_(2)` in aqueous medium also
Therefore for quantivative estimiation of aqueous `Fe(NO_(3))_(2)` it is not a suitable reagent
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Standard electrode potential data are useful for understanding the suitability of an oxidant in a redox titration. Some half cell reaction and their standard potentials are given below: MnO_(4)^(-)(aq) +8H^(+)(aq) +5e^(-) rarr Mn^(2+)(aq) +4H_(2)O(l) E^(@) = 1.51V Cr_(2)O_(7)^(2-)(aq) +14H^(+) (aq) +6e^(-) rarr 2Cr^(3+)(aq) +7H_(2)O(l), E^(@) = 1.38V Fe^(3+) (aq) +e^(-) rarr Fe^(2+) (aq), E^(@) = 0.77V CI_(2)(g) +2e^(-) rarr 2CI^(-)(aq), E^(@) = 1.40V Identify the only incorrect statement regarding quantitative estimation of aqueous Fe(NO_(3))_(2)

Two half-reactions of an electrochemical cell are given below : MnO_(4)^(-)(aq)+8H^(+)(aq)+5e^(-) toMn^(2+)(aq)+4H_(2)O(l), E^(@)=+1.51" V" Sn^(2+)(aq) to Sn^(4+)(aq)+2e^(-),E^(@)=-0.15" V"

Complete the following chemical equations : (i) MnO_(4)^(-) (aq) + S_(2)O_(3)^(2-) (aq) + H_(2) O(l) to1 (ii) Cr_(2)O_(7)^(2-) (aq) + Fe^(2+)(aq) + H^(+) (aq) to

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