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The cell Zn | Zn^(2+)(1 M)||Cu^(2+)(1 M)...

The cell `Zn | Zn^(2+)(1 M)||Cu^(2+)(1 M)|Cu`
`E_("cell")^(@)=1.10 V` was allowed to be copletely discharged at 298 K The relative concentration of `(Zn^(2+))/(Cu^(2+))` is

A

`antilog (24.08)`

B

`37.2`

C

`10^(37.2)`

D

`9.65xx10^(4)`

Text Solution

Verified by Experts

The correct Answer is:
D

Cell is completely discharged it means when equilibrium gets established `E_(cell) =0`
`Zn|Zn^(2+) (1M)||Cu^(2+)(1 M)|Cu`
`k_(eq)=[(Zn^(2+))]/[(Cu^(2+))]`
`log k_("eq") =(E_("cell")^(@))/(0.591)=(2xxx1.1)/(0.591)=37.2`
`k_("eq") =10^(37.2)`
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