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The standard electrode potentials for th...

The standard electrode potentials for the ractions
`Ag^(+)(aq)+e^(-) rarr Ag(s)`
`sn^(+)(aq)+2e^(-)rarrSn(s)`
at `25^(@)C` are 0.80 V and -0.14 V respectively the emf of the cell `Sn|Sn^(2+)|(1 M)|Ag^(+)(1M)|` Ag is

A

0.48 V

B

0.80 v

C

1.08 V

D

0.94 V

Text Solution

Verified by Experts

The correct Answer is:
D
EMF of the cell `=E_("left")-E_("right")`
`=0.80 (-0.14) =0.94 V`
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The standard electrode potential for the reactions, Ag^(+)(aq)+e^(-) rarr Ag(s) Sn^(2+)(aq)+2e^(-) rarr Sn(s) at 25^(@)C are 0.80 volt and -0.14 volt, respectively. The emf of the cell Sn|Sn^(2+)(1M)||Ag^(+)(1M)Ag is :

The standard electrode potentials for the reactions, Ag^(+) (a.q) + e^(-) rarr Ag (s) Sn^(2+) (a.q) + 2e^(-) rarr Sn (s) at 25^(@)C are 0.80 volt and -0.14 volt respectively. The emf of the cell Sn|Sn^(2+) (1M)|| Ag^(+) (1M) | Ag is:

The standard rectuion potentials for two half-cell reactions are given below Cd^(2+)(aq)+2e^(-)rarrCd(s),E^(@)=-0.40V Ag^(+)(aq)+e^(-)rarrAg(s),E^(@)=0.80V The standard free energy change for the reaction 2Ag^(+)(aq)+Cd(s)rarr2Ag(s)+Cd^(2+)(aq) is given by

Ag^(+)(aq)+e^(-)rarrAg(s) E^(@)=0.80V Cu^(2+)(aq)+2e^(-)rarrCu(s) E^(@)=0.34V Which expression gives the voltage for this cell if [Cu^(2+)]=1.00M and [Ag^(+)]=0.010M ?

Use the standard reduction potentials: Sn^(2+)(aq) + 2e^(-) rightarrow Sn(s) E^(@) = -0.141V Ag^(+)(aq) + e^(-) rightarrow Ag(s) E^(@) = 0.800V To calcultate E^(@) for the reaction: Sn(s) + 2Ag^(+)(aq) rightarrow Sn^(2+)(aq) + 2Ag(s)

The standard reduction potential for Fe^(2+) //Fe and Sn^(2+) //Sn electrodes are -0.44 and -0.14 volt respectively. For the given cell reaction Fe^(2+) + Sn rarr Fe + Sn^(2+) , the standard EMF is.

MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-ELECTROCHEMISTRY-Exercise 2
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