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A particle moves in a circular path of r...

A particle moves in a circular path of radius 0.5 m with a linear speed of 2 `ms^(-1)` ,its angular speed is

A

`2 rad s^(-1)`

B

`3rad s^(-1)`

C

`4rad s^(-1)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
Given ,radius ,r=0.5m
linear speed,v=2` ms^-1`
angular speed ,`omega`= ?
The angular speed is `omega=v/r=2/0.5=4rad s^(-1)`
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