The angular velocity of a particle is given by the equation `omega =2t^(2)+5rads^(-1)`. The instantaneous angular acceleration at t=4 s is

Options

A. `16 rad s^(-2)`
B. `19 rad s^(-2)`
C. `10 rad s^(-2)`
D. `12 rad s^(-2)`

Answer

A

Explanation

Given,`omega=2t^2+s`
We know that , `alpha_("inst")=(d)/(dt)omega` On putting the value of `omega`, We get
`therefore " " alpha_("inst")=(d)/(dt)( 2t^(2)+5)=4t+0`
`therefore " " alpha_("inst")=4xx4`
`t=4s=16rads^(-2)`