A particle moves throught angular displacement `theta` on a circlur path of radius r. The liner displacement wil be

Options

A. `2 r sin (theta//2)`
B. `2 r cos (theta//2)`
C. `2 r tan (theta//2)`
D. `2r cot (theta//2)`

Answer

A

Explanation

`Delta r = r_(2) - r_(1)` where `r_(2) = r_(1) = r`

Hence `Deltar= sqrt(r_(2)^(2) + r_(1)^(2) - 2r_(2)r_(1)cos theta ) = 2r sin.(theta)/(2)`