The ratio of angular speed of a second-had to the hour-hand of a watch is

Options

A. `3600: 1`
B. `720 : 1`
C. `72 :1`
D. `60:1`

Answer

B

Explanation

We know that angualr speed of a watch .
` omega = (theta)/(t) rArr omega prop (1)/(t)`
Hence `(omega_(sec))/(omega_(hours)) = (t_(hours))/(t_(sec)) `
` = (12 xx 3600)/(60) = 720 = (720)/(1)`