If the length of second's hand of a clock is 10cm , the speed of its dip `("in" cm^(-1))`is nearly .

Options

A. 2
B. 0.5
C. 1
D. 3

Answer

C

Explanation

We know that ,`omega=2pi rad 60s =(pi)/(30)rads^(-1)`
`therefore " "v =romega=10xx(pi)/(30)=(pi)/(3)rads^(-1)" "(because r=10cm)`
`(3.14)/(3) rads^(-1)=1.046overset~- 1cms^(-1)`