A particles is moving along a circular path of radius 5 m , moving with a uniform speed of `5ms^(-1)` . What will be the avetage acceleration, Whan the particle completes half revolution?

Options

A. zero
B. `10pims^(-2)`
C. `pi//ms^(-2)`
D. None of these

Answer

d

Explanation

The change in velocity ,when the particle completes half the revolution is given by
`Deltav =5m//s-(-5m//s)=10m//s `
now , the time taken to complete half the revolution is given by `t=(pir)/(v)=pi`
So,the average acceleration `=(Deltav)/(t)=(10)/(pi)m//s ^(2)`