A particles is moving along a circular p...

A particles is moving along a circular path of radius 5 m , moving with a uniform speed of `5ms^(-1)` . What will be the avetage acceleration, Whan the particle completes half revolution?

zero

`10pims^(-2)`

`pi//ms^(-2)`

None of these

Text Solution

Verified by Experts

The correct Answer is:

The change in velocity ,when the particle completes half the revolution is given by
`Deltav =5m//s-(-5m//s)=10m//s `
now , the time taken to complete half the revolution is given by `t=(pir)/(v)=pi`
So,the average acceleration `=(Deltav)/(t)=(10)/(pi)m//s ^(2)`

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A particle is moving along a circular along a circular path of radius 5 m with a uniform speed 5ms^(-1) . What will be the average acceleration when the particle completes half revolution?

Zero

`10ms^(-2)`

`10pims^(-2)`

`(10)/(pi)ms^(-2)`

A partical is moving along a circular path of radius 5m and with uniform speed 5 m//s . What will be the avarage acceleration when the partical completes half revoluation?

zero

`10m//s^(2)`

`10pm//s^(2)`

`(10//pi)m//s^(2)`

A particle is moving along a circular path of radius 6 m with uniform speed of 8 ms^(–1) . The average acceleration when the particle completes one half of the revolution is -

`(16)/(3pi)m//s^(2)`

`(32)/(3pi) m//s^(2)`

`(64)/(3pi)m//s^(2)`