One end of a string of length 1.0 m is tied to a body of mass 0.5 kg . It is whirled in a vertical circle with angular frequency `4 rads^(-1)`.The tension in the string when the body is at the lower most points of its motion will be equal to `(Take ,g =10ms^(-2))`

Options

A. 3N
B. 5N
C. 8N
D. 13N

Answer

D

Explanation

We can write tension at the lower most poits as
`T=mg+momega^(2)r`
`=(0.5)(10)+0.5xx(4)^(2)(1)`
`T=5+8=13 N`