A partical is moving along a circular path of radius `5m` and with uniform speed `5 m//s`. What will be the avarage acceleration when the partical completes half revoluation?

Options

A. Zero
B. `10 ms^(-2)`
C. `10 pi ms^(-2)`
D. `(10)/(pi) "ms"^(-2)`

Answer

D

Explanation

When the particle completes half revolution , change in volocity . `Deltav=[5-
(-5)]ms^(-1)=10ms^(-1)`
Time taken to complete the half revolution is
`t=(pir)/(v)=(pixx5)/(5)=pisec`
Thus ,average acceleration , `a_v=(Deltav)/(t)=(10)/pims^(-2)`