The coefficient of friction between the tyres and the road is 0.25. The maximum speed with which a car can be driven round a curve of radius 40 m without skidding is (assume `g = 10 ms^(-2)`)

Options

A. `40ms^(-1)`
B. `20ms^(-1)`
C. `15ms^(-1)`
D. `10ms^(-1)`

Answer

D

Explanation

For turning around a curve , centripetal force is provided by friction , so
`(mv^2)/(r)ltF or(mv^2)/(r)ltmumg rArrvltsqrt(mugr)`
`therefore" "v_(max)=sqrt(mugr)`
On substituting ,`mu` =0.25,r =40m, g=10`ms^(-2)` , We get `v_(max)=ms^(-1)`