A body moves along a circular path of radius 10m and the coefficient of friction is 0.5.What should be its angular speed `(in rad s^(-1))`, if is not to slip from the surface ? `(Given,g =9.8ms^(-2))`

Options

A. 5
B. 10
C. 0.1
D. 0.7

Answer

D

Explanation

For moving on circular path without slipping , Centripetal force must equal frictional force.
`i.e. (mv^2)/(r)=mumgrArrmromega^2=mumg" "(thereforev=romega)`
`or" " romega^2=mugrArr10omega^2=0.5xx9.8`
or `omega=sqrt((0.5xx9.8)/(10))=0.7rads^(-1)`