body is just being revolved in a vertical circle of radius R with a uniform speed. The string breaks when the body is at the highest point. The horizontal distance covred by the body after the string breaks is

Options

A. `2R`
B. `R`
C. `Rsqrt(2)`
D. `4R`

Answer

A

Explanation

As the body just complete the circular path , hence critical speed at the highest points .
`v_H=sqrt(gR)`
which is totally horizontal .
Time taken by the body to reach the ground,
`t=sqrt((2h)/(g))=sqrt((2xx2R)/(g)`
Hence , horizontal distance covered by the body
`=V_Hxxt=sqrt(gR)xxsqrt((4R)/(g))=2R`