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A body of mass 1 kg is rotating in a ver...

A body of mass 1 kg is rotating in a verticle circle of radius 1 m .What will be the difference in its kinetic energy at the top and bottom of the circle ?
`(g=10m//s^(2))`

A

50J

B

30 J

C

20 J

D

10 J

Text Solution

Verified by Experts

The correct Answer is:
C
Speed at the top is `sqrt(gr)` and that at the bottom is `sqrt(5gr)`.
`therefore" " k_b-k_7=1/2m[5gr-gr]=2mgr`
`=2xx1xx10xx1=20J`
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