A weightless thread can bear tension upto 37 N . A stone of mass 500 g is tied to it and revolved in a circular path of radius 4 m in a vertical plane . If g =10`ms^(-2) `, then the maximum angular velocity of the stone will be

Options

A. `2rad s^(-1)`
B. `4rad s^(-1)`
C. `8rad s^(-1)`
D. `16rad s^(-1)`

Answer

B

Explanation

Maximum tension in the thread is given by
`T_(max)=mg+(mv^(2))/(r)=mg+mromega^2(becausev =romega)`
or `omega^2=(T_(max)-mg)/(mr)`
`therefore" "omega^2=(37-0.5xx10)/(0.5xx4)=(37-5)/(2)`
`or omega^2=16`
or Maximum angular velocity `omega=4rads^(-1)`