The moment of inertia of a circular dics...

The moment of inertia of a circular dics about one of its diameters is l. What will be its moment of inertia about a tangent parallel to the diameter?

`4l`

`2l`

`(5l)/(2)`

`5l`

Text Solution

Verified by Experts

The correct Answer is:

The moment of inertia of a circular disc about one of its diameters, `l=(1)/(4)MR^(2)`
`therefore" "MR^(2)=4l`
`therefore" "` Ml about a tangent parallel to the diamater,
`l=l_(CM)+MR^(2)` (According to the parallel axes theorem)
`=(1)/(4)MR^(2)+MR^(2)=(5MR^(2))/(4)=5l" "(therefore MR^(2)=4l)`

Topper's Solved these Questions

ROTATIONAL MOTION'
MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise PRACTICE EXERCISE (Exercise 2 (MISCELLANEOUS PROBLEMS))|47 Videos
ROTATIONAL MOTION'
MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET Corner|35 Videos
ROTATIONAL MOTION'
MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET Corner|35 Videos
REFRACTION OF LIGHT
MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise Exercise 2|25 Videos
SCALARS AND VECTORS
MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise Exercise 2 (Miscellaneous Problems)|20 Videos

The moment of inertia of a circular ring about one of its diameters is I . What will be its moment of inertia about a tangent parallel to the diameter?

4 I

2 I

`(3)/(2) I`

`3 I`

The moment of inertia of a ring about one of its diameter is 2 kg m^(2) . What will be its moment of inertia about a tangent parallel to the diameter?

`2 kg m^(2)`

`6 kg m^(2)`

`4 kh m^(2)`

`5 kg m^(2)`

The moment of inertia of a ring about one of it's diameter is I. What will be the moment of inertia about a tangent parallel to the diameter?

`3/2` I