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Three point masses, each of mass `m`, are placed at the corners of an equilateral triangle of side `L`. The moment of inertia of this system about an axis along one side of the triangle is

A

`3ml_(2)`

B

`(3)/(2)ml^(2)`

C

`ml^(2)`

D

`(3)/(4)ml^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D

Distance of corner mass from opposite side,
`r=sqrt(l^(2)-(l//2)^(2))=(sqrt3)/(2)l`
`"and "l=mr^(2)=(3)/(4)ml^(2)`
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