A mass is whirled in a circular path with a constant angular velocity and its angular momentum is L. If the string is now halved keeping the angular velocity same, the angular momentum is

Options

A. `L//4`
B. `L//2`
C. less than one
D. 2 L

Answer

A

Explanation

Angular momentum, `L=lomega=ml^(2)omega`
When l is halved, new angular momentum
`L'=m(l//2)^(2)omega=(ml^(2)omega)/(4)=(L)/(4)`