When a disc is rotating with angular velocity `omega` , a particle situated at a distance of 4 cm just begins to slip . If the angular velocity is doubled , at what distance will the particle start to slip ?

Options

A. 1 cm
B. 2 cm
C. 3 cm
D. 4 cm

Answer

A

Explanation

Angular velocity `=omega`
Centripetal force, `F=mromega^(2) or r prop (1)/(omega^(2))`
`therefore" "(r_(1))/(r_(2))=(omega_(2)^(2))/(omega_(1)^(2))`
`"or "3(4)/(r_(2))=(4omega^(2))/(omega^(2)) rArr r_(2)=1cm`