The moment of inertia of a uniform thin rod of length `L` and mass `M` about an axis passing through a point at a distance of `L//3` from one of its ends and perpendicular to the rod is

Options

A. `(ML^(2))/(12)`
B. `(ML^(2))/(9)`
C. `(7ML^(2))/(48)`
D. `(ML^(2))/(48)`

Answer

B

Explanation

`l_("CM")=(ML^(2))/(12)` (about middle point)

`therefore" "l=l_("CM")+Mx^(2)=(ML^(2))/(12)+M((L)/(6))^(2)=(ML^(2))/(9)`