Moment of inertia of a rod of mass M and length L about an axis passing through a point midway between centre and end is

Options

A. `(ML^(2))/(6)`
B. `(ML^(2))/(12)`
C. `(7ML^(2))/(24)`
D. `(7ML^(2))/(48)`

Answer

D

Explanation

`l=l_("CM")+Mx^(2)`

`=(ML^(2))/(12)+m[(L)/(4)]^(2)`
`=(ML^(2))/(12)+(ML^(2))/(16)=(7ML^(2))/(48)`