The moment of inertia of a uniform circular disc of radius `R` and mass `M` about an axis passing from the edge of the disc and normal to the disc is.

Options

A. `MR^(2)`
B. `(2)/(5)MR^(2)`
C. `(3)/(2)MR^(2)`
D. `(1)/(2)MR^(2)`

Answer

C

Explanation

The moment of inertia about an axis passing through centre of mass of disc and perpendicualr to its plane is
`l_("CM")=(1)/(2)MR^(2)`
where, M is the mass of disc and R its radius. Accoding to theorem of parallel axes, moment of inertia of circular disc about an axis touching the disc at its diameter and normal to the disc is
`=l_("CM")+MR^(2)=(1)/(2)MR^(2)+MR^(2)=(3)/(2)MR^(2)`