An electrical heating element which has an AC resistance of 60 `Omega` is connected across a 240 V AC supply. Calculate the current drawn from the supply and power consumed by heatint element.

Options

A. 4.0 A, 960 W
B. 2.9 A, 440 W
C. 10 A, 50 W
D. 4A, 490 W

Answer

A

Explanation

Given, `V=240V,R=60Omega`
The supply current `(I)=(V)/(R)=(240)/(60)=4.0A`
The active power consumed by the AC resistance is
`P=I^(2)R=(4.0)^(2)60=960W`