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A choke coil having a resistance of 10Om...

A choke coil having a resistance of `10Omega` and inductance of 0.5 H is connected in series with a capacitor of 2.5 `muF`. The whole circuit has been connected to 230 V, 50 Hz supply. Calculate the value of current flowing through the circuit.

A

0.487 A

B

0.308 A

C

0.206 A

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To calculate the current flowing through the circuit, we need to follow these steps: ### Step 1: Calculate the Capacitive Reactance (Xc) The capacitive reactance (Xc) can be calculated using the formula: \[ X_c = \frac{1}{\omega C} \] where: - \(\omega = 2\pi f\) (angular frequency), - \(f = 50 \, \text{Hz}\), - \(C = 2.5 \, \mu F = 2.5 \times 10^{-6} \, F\). First, calculate \(\omega\): \[ \omega = 2\pi \times 50 \approx 314.16 \, \text{rad/s} \] Now, substitute the values into the formula for \(X_c\): \[ X_c = \frac{1}{314.16 \times 2.5 \times 10^{-6}} \approx 1273.88 \, \Omega \] ### Step 2: Calculate the Inductive Reactance (Xl) The inductive reactance (Xl) can be calculated using the formula: \[ X_l = \omega L \] where: - \(L = 0.5 \, H\). Substituting the values: \[ X_l = 314.16 \times 0.5 \approx 157.08 \, \Omega \] ### Step 3: Calculate the Impedance (Z) The total impedance (Z) in a series circuit with resistance (R), inductive reactance (Xl), and capacitive reactance (Xc) is given by: \[ Z = \sqrt{R^2 + (X_c - X_l)^2} \] where: - \(R = 10 \, \Omega\). Substituting the values: \[ Z = \sqrt{10^2 + (1273.88 - 157.08)^2} \] Calculating \(X_c - X_l\): \[ X_c - X_l = 1273.88 - 157.08 = 1116.80 \, \Omega \] Now substituting back into the impedance formula: \[ Z = \sqrt{10^2 + (1116.80)^2} = \sqrt{100 + 1247404.64} \approx \sqrt{1247504.64} \approx 1116.90 \, \Omega \] ### Step 4: Calculate the Current (I) Using Ohm's law, the current can be calculated as: \[ I = \frac{V}{Z} \] where: - \(V = 230 \, V\). Substituting the values: \[ I = \frac{230}{1116.90} \approx 0.205 \, A \] ### Final Answer The value of the current flowing through the circuit is approximately: \[ I \approx 0.205 \, A \] ---

To calculate the current flowing through the circuit, we need to follow these steps: ### Step 1: Calculate the Capacitive Reactance (Xc) The capacitive reactance (Xc) can be calculated using the formula: \[ X_c = \frac{1}{\omega C} \] where: ...
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