In a transformer, number of turns in the primary coil are 140 and that in the secondry coil are 280. If current i primary ciol is 4A, then that in the secondary coil is

Options

A. 4A
B. 2A
C. 6A
D. 10A

Answer

B

Explanation

Given, number of turns in primary coil, `N_(1)=140`
number of turns in secondary, coil `N_(2)=280`
current in primary coil, `i_(p)=4A`
current in secondary coil `i_(s)=?`
`(N_(p))/(N_(s))=(V_(p))/(V_(s))=(i_(s))/(i_(p))`
`therefore i_(s)=(N_(p)i_(p))/(N_(s))=(4xx140)/(280)=2A`