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A circular ring of diameter 20cm has a r...

A circular ring of diameter 20cm has a resistance `0.01Omega` How much charge will flow through the ring if it is rotated from positon perpendicular to the uniform magnetic field of B=2T to a position parallel to field?

A

63 C

B

0.63 C

C

6.3 C

D

0.063 C

Text Solution

Verified by Experts

The correct Answer is:
C
`q=(dphi)/(R)=(BA(cos0^(@)-cos90^(@)))/(R)`
`=(2xx3.143xx(10^(-1))^(2))/(0.01)`
`q=6.286C=6.3C`
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-ELECTROMAGNETIC INDUCTION-Example 1
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  16. A very small circular loop of radius a is initially (at t = 0) coplana...

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  17. The wing span of an aeroplane is 36 m. if the plane is flying at 400km...

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