A solenoid 30 cm long is made by winding 2000 loops of wire on an iron rod whose cross-section is `1.5cm^(2)`. If the relative permeability of the iron is 6000. what is the self-inductance of the solenoid?

Options

A. 1.5 H
B. 2.5 H
C. 3.5 H
D. 0.5 H

Answer

A

Explanation

Self-inductance of the solenoid,
`L=(mu_(r)*mu_(0)N^(2)A)/(l)`
`=(600xx4pixx10^(-7)xx(2000)^(2)xx(1.5)xx10^(-4))/(0.3)=1.5H`