Two inductors each of inductance `L` are joined in parallel. Their equivalent inductance is

Options

A. zero
B. `L/2`
C. `L`
D. `3L`

Answer

B

Explanation

Inductance of Ist inductor, `L_(1)=L`
Inductance of Iind inductor, `L_(2)=L`
Now, if these inductors are connected in parallel their equivalent inductance will be
`(1)/(L_(eq))=(1)/(L_(1))+(1)/(L_(2))=(1)/(L)+(1)/(L)=(2)/(L)`
Hence, `L_(eq)=(L)/(2)`