The number of turns of primary and secondary coils of a transformer are 5 and 10 respectively and the mutual inductance of the tranformar is 25 henry. Now the number of turns in the primary and secondary of the transformar are made 10 and 5 respectivaly. The mutual inductance of the transformar in henry will be

Options

A. 25 H
B. 12.5 H
C. 50 H
D. 6.25 H

Answer

A

Explanation

Mutual inductance of transfomer,
`M prop N_(1)N_(2)`
`(M_(1))/(M_(2))=(N_(1)N_(2))/(N_(1)'N_(2)')`
`(25)/(M_(2))=(5xx10)/(10xx5)=M_(2)=25H`