The self inductance of a coil which produces 5V when the current changes from 3A to 2A in one millisecond is

Options

A. 5000 H
B. 5 mH
C. 50 H
D. 5 H

Answer

B

Explanation

`L=?,e=5V,(dl)/(dt)=((2-3))/(10^(-3))=-10^(3)As^(-1)`
As, `e=-L(dl)/(dt)`
`therefore 5=-L(-10^(3)),L=(5)/(10^(3))H=5mH`