Two coils A and B have 200 and 400 turns respectively. A current of 1 A in coil A causes a flux per turn of `10^(-3)` Wb to link with A and a flux per turn of `0.8xx10^(-3)` Wb through B. the ratio of mutual inductance of A and B is

Options

A. 0.625
B. 1.25
C. 1.5
D. 1.625

Answer

A

Explanation

From `phi=Mi`
`(M_(1))/(M_(2))=(phi_(1))/(phi_(2))=(10^(-3)xx200)/(0.8xx10^(-3)xx400)=(10)/(16)=0.625`