The peak vlaue of alternating current is `5sqrt(2)`. The mean square value fo current will be

Options

A. `5A`
B. `2.5 A`
C. `5sqrt(2)A`
D. None of these

Explanation

To find the mean square value of the alternating current given its peak value, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Peak Value**:
The peak value of the alternating current (I_peak) is given as \( 5\sqrt{2} \) amperes.

2. **Use the Formula for RMS Current**:
The root mean square (RMS) value of the alternating current is calculated using the formula:
\[ I_{RMS} = \frac{I_{peak}}{\sqrt{2}} \]

3. **Substitute the Peak Value**:
Substitute the peak value into the formula:
\[ I_{RMS} = \frac{5\sqrt{2}}{\sqrt{2}} \]

4. **Simplify the Expression**:
The \(\sqrt{2}\) in the numerator and denominator cancels out:
\[ I_{RMS} = 5 \text{ amperes} \]

5. **Conclusion**:
The mean square value of the current, which is the RMS value, is therefore \( 5 \) amperes.

### Final Answer:
The mean square value of the current is **5 amperes**.

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