The average power dissipated in AC circuit is 2W. If a current flowing throuh a circuit is 2A, impedance is `1Omega`, then what is the power factor of the circuit?

Options

A. `0.5`
B. `1`
C. zero
D. `(1)/(sqrt(2))`

Answer

A

Explanation

As average power, `P=2W,l_(rms)=2A`
Impedence, Z=`1Omega`
Power factor factor `(cosphi)=?`
We know that `P=V_(rms)xxi_(rms)*cosphi`
`P=i_(rms)^(2)Z*cosphi`
`P=i_(rms)^(2)Z*cosphi" "(becuaseV_(rms)=i_(rms)*Z)`
`cosphi=(P)/(i_(rms)^(2)*Z)=(2)/((2)^(2)xx1)=(2)/(4)(1)/(2)=0.5`