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An inductive coil has a resistance of 10...

An inductive coil has a resistance of `100 Omega`. When an AC signal of frequency 1000 Hz is applied to the coil, the voltage leads the current by `45^(@)`. What is the inductance of the coil?

A

`(1)/(10pi)`

B

`(1)/(20pi)`

C

`(1)/(40pi)`

D

`(1)/(60pi)`

Text Solution

Verified by Experts

The correct Answer is:
B
`tanphi=(X_(L))/(R)`
`therefore tan45^(@)=(Lomega)/(R)`
`L=(R)/(omega)=(100)/(2pixx1000)" "(because tan45^(@)=1)`
`L=(1)/(20pi)`
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-ELECTROMAGNETIC INDUCTION-Example 1
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