The instantaneous values of current and voltage in an AC circuit are given by
l = 6sin ( 100`pi`t + `pi` / 4)
V = 5sin ( 100 `pi`t - `pi` / 4 ), then

Options

A. The instantaneous values of current and voltage in an `l=6sin(100pit+(pi)/(2)),V=5sin(100pit-(pi)/(2))`, ten
B. current leads the voltage by `45^(@)`
C. voltage leads the current by `90^(@)`
D. current leads the voltage by `90^(@)`

Answer

C

Explanation

The phase difference between instantaneous value of I and V is
`(pi)/(4)-(-(pi)/(4))=(pi)/(2)`
hence, current leads the voltage by `90^(@)`