In the non-resonant circuit, what will be the nature of the circuit for frequencies heigher than the resonant frequency?

Options

A. Resistive
B. capacitive reactance is doubled, the current is halved
C. Inductive
D. None of these

Answer

C

Explanation

At resonant frequency,
`X_(L)=X_(C)" "(becauseomegaL=(1)/(omgaC))`
The frequency are higher than resonance frequencies.
`X_(L) gt X_(C)`
i.e. behvaiour is inductive.