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An alternating voltage E=200sqrt(2)sin(1...

An alternating voltage `E=200sqrt(2)sin(100t)` is connected to a `1` microfarad capacitor through an AC ammeter. The reading of the ammeter shall be

A

10 mA

B

20 mA

C

40 mA

D

80 mA

Text Solution

Verified by Experts

The correct Answer is:
B
As `V=200sqrt(2)sin(100t)`
Hence, `V_(rms)=200V and omega=100s^(-1)`
Moreover, `C=1muF=10^(-6)F`
`therefore l=(V_(rms))/(X_(C))=V_(rms)xxCxxomega`
`=200xx10^(-6)xx100`
`=2xx10^(-2)A=20mA`
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