In the circuit shown here, the point C is kept connected to the point A till the current flowing through the circuit becomes constant. Afterward, suddenly ponit C is disconnected from point A and connected to point B at time t=0. ratio of voltage across resistance and the inductor at t=L/R will be equal to

Options

A. `(e)/(1-e)`
B. `1`
C. `-1`
D. `(1-e)/(e)`

Answer

C

Explanation

After connecting C to B (hanging the switch), the circuit will act like an L R discharging circuit.

Applying Kirchhoff's loop equation, then we get
`V_(R)+V_(L)=0 implies V_(R)=-V_(L)`
`(V_(R))/(V_(L))=-1`